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The Pendulum Equation and how it applies to clocks
| The Pendulum Equation is: | ![]() |
Where:
T = period (time for one full swing) in seconds
= the constant pi,
3.14159, used in geometry involving circles and arcs
L = length of the pendulum arm in metres (or
feet)
g = acceleration due to gravity: 9.81 m/s2 (or 32.2 ft/s2)
Some notes on a pendulum system:
1. The mass on the end has no effect on the period.
2. The length of the arm is what affects the period..
3. The angle of release has no real effect on the period.
4. A pendulum movement is a resonant system with a one resonant
frequency: 1 Hz, or once a second movement through one point.
A pendulum is a falling object, and is subject to
the forces of gravity. Do you remember that all objects in a
vacuum fall at the same speed? Or that a marble and a bowling
ball both fall at the same speed? That is why the mass (weight)
of the pendulum does not matter for the period, the acceleration
due to gravity is the same for all objects. The force of gravity
(it's value in the equation above) changes a little based on your
elevation and a few other things, but for the sake of clocks the
gravity value for the equation above is just fine.
Notice that the period T depends on the length of the
pendulum directly. As L gets larger, so will T. So
to slow down the clock, increase L by moving the
weight on the pendulum lower. Conversely, to speed up the clock
move the weight higher up.
This isn't a linear relation, since there is a square root in the
equation. That means that to accurately adjust a clock, you have
to average in many cycles (swings) of the pendulum. The section
below shows a method to use for setting clock accuracy.
A good Pendulum discussion can be found here: http://hyperphysics.phy-astr.gsu.edu/hbase/pend.html
Want an intensely scientific discussion of pendulum's and
accuracy?? Click here: http://www.ubr.com/ftp/pendulum.pdf
For an even better discussion on "The pendulum equation and how it applies to clocks", see the paper excerpt below from David LaBounty, used by permission.
Clock Beat Rates
By David J. LaBounty CMC, FBHI
With the advent of the new digital timing machines it has become easier to rate a clock using its beat rate. Beat rate is defined as the number of blows of the escape wheel teeth as they fall on the lock faces of the pallets in a given time period. This time period is usually measured in hours or minutes. The beat rate in most clock timers is in beats per hour or BPH. In order for a clock to keep time, the pendulum length must be matched to the gear ratios of the movement to achieve a correct beat rate. The beat rate for a specific clock to keep time is a constant no matter where you are in the world, provided the gearing hasn't been modified from its original design. Using a timer to make adjustments to the pendulum length to get the correct beat rate is a fast, easy method and can be very accurate
Variations in acceleration due to gravity (g) also play a role in determining the length of a pendulum, and it is important to understand how that relates to beat rate. The variation in g is greatest when traveling in a North-South direction rather than in an East-West. 65% of the variation when traveling North-South is due to the rotational affect of the earth. This will have the effect of counteracting g. 35% is due to the Equatorial Bulge which changes your distance from the center of the earth[1] (see table 1). Other affects on g are changes in altitude (see table 2), and local variations due to the Earth's non-uniform surface density. As you move about the earth, g increases or decreases. This means that a pendulum will have to be lengthened or shortened in order to obtain a correct beat rate. It is for this reason that we must consider what the French used as the value for the acceleration due to gravity (g). Was it the value of g in London, Paris, the equator, the poles, or somewhere else? We must assume that the numbers stamped on the back plate represent a specific measurable length, and that the length was calculated using known equations which rely on the value of g.
| Table 1--The different values of g over various latitudes[2] | Table 2--The different values of g over various altitudes | ||||||
| Latitude | g (circa 1916) | Pendulum Length (PL) |
Altitude at 45 deg. latitude |
g (circa 1982) | (PL) | ||
| 0 deg | 385.034 "/s2 | 39.0121" | 0.000 miles | 386.063 "/s2 | 39.1164" | ||
| 10 deg | 385.099 "/s2 | 39.0184" | 0.621 miles | 385.945 "/s2 | 39.1044" | ||
| 20 deg | 385.274 "/s2 | 39.0365" | 2.486 miles | 385.591 "/s2 | 39.0685" | ||
| 30 deg | 385.548 "/s2 | 39.0642" | 4.971 miles | 385.118 "/s2 | 39.0206" | ||
| 40 deg | 385.884 "/s2 | 39.0982" | 9.942 miles | 384.134 "/s2 | 38.9209" | ||
| 50 deg | 386.240 "/s2 | 39.1344" | 19.884 miles | 382.283 "/s2 | 38.7334" | ||
| 60 deg | 386.576 "/s2 | 39.1683" | 62.137 miles | 377.953 "/s2 | 38.2946" | ||
| 70 deg | 386.850 "/s2 | 39.1960" | 310.686 miles | 335.827 "/s2 | 34.0264" | ||
| 80 deg | 387.028 "/s2 | 39.2141" | 621.321 miles | 291.732 "/s2 | 29.5587" | ||
| 90 deg | 387.090 "/s2 | 39.2204" | 236,121.056 miles | 0.107 "/s2 | 0.0108" | ||
621.321 miles = height of a satellite 236,121.056 miles = height of the moon
So, what does
the value of g have to do with determining beat rate?
The value for acceleration due to gravity (g) is derived from
Newton's second law of motion:
F = ma
where: F = force, m = mass, and a =
acceleration
Let acceleration (a) equal acceleration due to gravity (g).
a = g.
Then F = ma becomes:
F = mg
Now consider Newton's law of gravitation:
m1m2
F = G ______
r2
Where: F = force between two particles having mass, m1
= mass of particle 1,
m2 = mass of particle 2, r =
distance between the two particles, and
G = universal gravitational constant = 6.6726 x 10-11
m3/kg s2
(the above value for this constant was adopted in 1982 and first accurately
measured by Lord Cavendish in 1798)
Letting m1 be the mass of our pendulum (m), m2 be the mass of the earth (Me), and r the radius of the earth (Re), we get:
mMe
GMe
F = G
______ = m
______
Re2
Re2
Therefore, from Newton's second law of motion F = mg, we see from the above equation:
GMe
g = ______
which is not a constant and varies with location. (see
table 1 & 2)
Re2
Where:
G =
6.6726 x 10-11 m3/kg s2
Me = 5.97 .
1024 kg or 6.6 . 1021 tons
Re = 6.37 . 106
m or 2.09 . 107 ft
(1982 values)
In physics, the period of oscillation of a simple pendulum (T) is equal to two times pi (p), times the square root of the pendulum length (PL), divided by the acceleration due to gravity (g).
T = 2p SQRT (PL/g)
Here, "period of oscillation" of a simple pendulum is taken as the time for the total angular travel of the pendulum. (see fig. 2)

This would mean that one beat is half of the period of oscillation since an escape wheel tooth receives a blow twice in each period of oscillation. To make matters more confusing, this half-period is also widely used as T. For clarity, I will use T1/2. Then we have:
T1/2 = p SQRT (PL/g)
If we let T1/2 = 1 sec. per beat and g = local acceleration due to gravity, the length of a seconds pendulum can be determined at our location. (see table 3)
1 sec/beat = p SQRT (PL/g)
Inverting we get beats per second (BPS):
SQRT
(g)
60 . SQRT (g)
1 BPS = __________
or 1 BPM = __________
pSQRT (PL) pSQRT
(PL)
Squaring both sides gives:
3600 .
g
1 BPM2 = __________
p2
. PL
3600
. g
Now, let the pendulum constant Pc
= __________
p2
Then:
Pc
Pc
1 BPM2 = __________
or PL = __________
PL
BPM2
Which are dependent on location because Pc is dependent on g.
Converting to BPH:
3600 . Pc
1 BPH2 = __________
PL
And finally:
1 BPH = SQRT (3600 . Pc/PL)
| Table 3--PL values for a seconds pendulum [3] | ||||||
| PL (") | Pc | g ("/sec2) | g (m/sec2) | |||
| Equator | 39 | 140400 | 384.9146 | 9.7768 | ||
| New York | 39.1012 | 140764 | 385.9125 | 9.8022 | ||
| Paris | 39.13 | 140868 | 386.1976 | 9.8094 | ||
| London | 39.14 | 140904 | 386.2963 | 9.8119 | ||
| Greenland | 39.20 | 141120 | 386.8885 | 9.8270 | ||
| Poles | 39.206 | 141142 | 386.9488 | 9.8285 | ||
We can derive a beat rate from the equation based on pendulum length and local pendulum constant, provided the numbers used for PL and Pc are accurate.
Remember, the purpose of this table is to aid in rating a clock. If the clock doesn't rate at the suggested BPH then there may be other factors involved such as altered, damaged, or switched parts. What counts is that the minute hand goes around the dial once every 60 minutes for the duration of its run.
References:
[1] Fundamentals of Physics Second ed.; Halliday and
Resnick; John Wiley & Sons, New York; 1981; pp. 218 - 254.
[2] Handbook of Chemistry and Physics, 5th ed.; The
Chemical Rubber Company; Cleveland, Ohio; 1916; pp. 244 - 249.
[3] The Modern Clock; Goodrich; North American Watch
Tool & Supply Co., IL; 1905; p. 12.
Method for Setting Clock
Accuracy
Important note: You can try using the pendulum equation.... but
you shouldn't, it will prove to be difficult in practice. You
will need the accurate length L which is
measured from the top attachment point to the end of the arm (not
the end of the weight) and that usually involves taking the clock
movement out of the case. If you take the clock movement out, you
will usually have to adjust everything when you put it back in -
chimes, clappers, gongs, alignment, weights, etc. It's just not
worth it and you could break something, use the steps below!!
1. Most pendulums have their weights near the
bottom of the length of the arm. To start the clock, gently push
the pendulum arm laterally (to a side) and release. Let the
pendulum swing about 10 times to reach a steady state
oscillation.
2. Watch or listen to the pendulum as it swings while watching a
modern watch. You should be able to tell if it swings
"mostly" on time, once a second. Only adjust the weight
at this point if it is obviously much faster or slower than your
modern clock.
3. Pick a consistent measuring point: the instant when the chimes
begin on the hour. When the chime begins, start a stopwatch
4. Wait just under an hour, and be ready for when the chimes
begin. When they begin, stop the stopwatch.
5. Determine how far off the pendulum clock is from the
stopwatch. Record the time as T1. If the stopwatch shows less
than an hour passed, move the weight lower. If the stopwatch
shows more than an hour passed, move the weight higher. Most arms
and weight systems have an adjustment, often a screw. If you turn
the screw or other locking device, make sure the weight moves
too!
6. Pick an amount to adjust, like 1/8 inch, or 4 turns of the
screw, or something similar.
7. Repeat steps 3 and 4 and get another time measurement. Record
the time as T2. Now, you have a measurement, an adjustment, and
another measurement. The difference between T2 and T1 is how much
your adjustment affected the time!!
8. Determine how much time you are off, divide that by the
adjustment time you just calculated in step 7, and then go ahead
- move the pendulum that many increments to get to the time
period you need! Then you'll need to do fine tuning again with
the final adjustment. As you go about your business, time the one
hour spacing and make fine adjustments to the pendulum to get the
clock accurate.
9. Fine Tuning: this process takes days. I have tried with my
pendulum clock to get it to be as accurate as a digital clock and
I just can't and that doesn't surprise me. The best I have done
is about 30seconds per day out of perfect accuracy. I set it
accurately one day, then wait a day and measure it again. If it's
a little slow or fast I move the weight screw one turn or less,
reset the clock, and wait another day. Putting the clock more
level helps.
You'll have to do this by trial and error, mostly; all clocks are
different, and just maybe elevation will begin to factor in! But
in general, after just a few hours, you will know pretty well how
far the pendulum will have to be adjusted to set the time
correctly. If you determine that the weight has to be moved
beyond the length of the arm, then you'll have to contact a clock
repair service, the spring may be worn out, but remember: adding
more weight won't help!!
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